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x^2-66x+305=0
a = 1; b = -66; c = +305;
Δ = b2-4ac
Δ = -662-4·1·305
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3136}=56$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-66)-56}{2*1}=\frac{10}{2} =5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-66)+56}{2*1}=\frac{122}{2} =61 $
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